A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals 5 mm. The least count of the device is
A vernier caliper has 10 main scale divisions coinciding with 11 vernier scale divisions. 1 main scale division equals 5 mm. The least count of the device is
Option 1 - <p><span lang="EN-IN"><!-- [if gte mso 9]><xml>
<o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025"
DrawAspect="Content" ObjectID="_1820219637">
</o:OLEObject>
</xml><![endif]-->1/2 mm</span></p>
Option 2 - <p><span lang="EN-IN"><!-- [if gte mso 9]><xml>
<o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025"
DrawAspect="Content" ObjectID="_1820219667">
</o:OLEObject>
</xml><![endif]-->5/12</span><span lang="EN-IN">mm</span></p>
Option 3 - <p><span lang="EN-IN"><!-- [if gte mso 9]><xml>
<o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025"
DrawAspect="Content" ObjectID="_1820219682">
</o:OLEObject>
</xml><![endif]-->5/11mm</span></p>
Option 4 - <p><span lang="EN-IN">0.3 mm</span></p>
1 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
Answered by
4 months ago
Correct Option - 3
Detailed Solution:
10 M = 11 V
Þ 1V =
Þ LC = |M – V|
=
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