At a point away from planet of radius 6400 km, the gravitational potential and field are –6.4 * 107 SI units and 6.4 SI units respectively. Find height of that point above surface of planet.

G M r = 6 . 4 * 1 0 7 . (i) G M r 2 = 6 . 4 . (ii) r = 6 . 4 * 1 0 7 6 . 4 = 107 m = 10,000 km R + h = 10,000 h = 10,000 – 6400 = 3600 km

**At a point away from planet of radius 6400 km, the gravitational potential and field are –6.4 * 10⁷ SI units and 6.4 SI units respectively. Find height of that point above surface of planet.**

Option 1 - 3000 km

Option 2 - 6400 km

Option 3 - 3600 km

Option 4 - 9400 km

1 Views|Posted 4 months ago

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Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

$\frac{G M}{r} = 6.4 * 1 0^{7}$ . (i)

$\frac{G M}{r^{2}} = 6.4$ . (ii)

$r = \frac{6.4 * 1 0^{7}}{6.4}$

= 10⁷ m

= 10,000 km

R + h = 10,000

h = 10,000 – 6400 = 3600 km

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