Match the two columns. Column 1 Column 2 P. Surface tension 1. [ML2T–2] Q. Viscosity 2. [ML2T–1] R. Angular momentum 3. [ML–1T–1] S. Rotational kinetic energy 4. [ML0T–2]

S = F L [S] = [MT–2] F = n A d v d x η = M L T − 2 ⋅ T L 2 = M L − 1 T − 1 L → = r → * p → L º [ML2T–1] K E = 1 2 l ω 2 KE º ML2T−2

Match the two columns.

Column 1

Column 2

P.

Surface tension

1.

[ML²T^–2]

Q.

Viscosity

2.

[ML²T^–1]

R.

Angular momentum

3.

[ML^–1T^–1]

S.

Rotational kinetic energy

4.

[ML⁰T^–2]

Option 1 - P–1, Q–2, R–3, S–4

Option 2 - P–4, Q–3, R–2, S–1

Option 3 - P–1, Q–3, R–4, S–2

Option 4 - P–4, Q–2, R–1, S–3

4 Views|Posted 4 months ago

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Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

$S = \frac{F}{L}$

[S] = [MT^–2]

$F = n A \frac{d v}{d x}$

$η = \frac{M L T^{- 2} \cdot T}{L^{2}} = M L^{- 1} T^{- 1}$

$\vec{L} = \vec{r} * \vec{p}$

L º [ML²T^–1]

$K E = \frac{1}{2} l ω^{2}$

KE º ML²T⁻²

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	Column 1		Column 2
P.	Surface tension	1.	[ML²T^–2]
Q.	Viscosity	2.	[ML²T^–1]
R.	Angular momentum	3.	[ML^–1T^–1]
S.	Rotational kinetic energy	4.	[ML⁰T^–2]