Osmotic pressure at 273 K is 7 * 105 Pa, then what will be the value of x, if its osmotic pressure at 283 K is x * 104 Pa?

π 1 = i C R T 1 π 2 = i C R T 2 π 1 T 1 = π 2 T 2 π 2 = π 1 * T 2 T 1 = 7 * 1 0 5 * 2 8 3 2 7 3 = 7.256 * 105 * Pa = 72.56 * 104 Pa p2 = x * 104 x = 72.56 » 73

**Osmotic pressure at 273 K is 7 * 10⁵ Pa, then what will be the value of x, if its osmotic pressure at 283 K is x * 10⁴ Pa?**

1 Views|Posted 4 months ago

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Alok Kumar Singh | Contributor-Level 10

4 months ago

$π_{1} = i C R T_{1}$

$π_{2} = i C R T_{2}$

$\frac{π_{1}}{T_{1}} = \frac{π_{2}}{T_{2}}$

$π_{2} = \frac{π_{1} * T_{2}}{T_{1}}$

$= \frac{7 * 1 0^{5} * 283}{273}$

= 7.256 * 10⁵ * Pa

= 72.56 * 10⁴ Pa

p₂ = x * 10⁴

x = 72.56 » 73

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