Potential energy function corresponding to conservative force is given as $U (x, y, z) = \frac{3 x^{2}}{2} + 5 y + 6 z$ , then the force at x = 6 is pN. The value of p upto its nearest integral value is

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alok kumar singh | Contributor-Level 10

a month ago

$F_{x} = \frac{- d v}{d x}$

$\vec{F} = - 3 x \hat{i} - 5 \hat{j} - 6 \hat{k}$

${| \vec{F} |}_{x = 6} = \sqrt[]{1 8^{2} + 5^{2} + 6^{2}}$

$= \sqrt[]{324 + 25 + 36}$

= $\sqrt[]{385}$

= 19.62N

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Potential energy function corresponding to conservative force is given as $U (x, y, z) = \frac{3 x^{2}}{2} + 5 y + 6 z$ , then the force at x = 6 is pN. The value of p upto its nearest integral value is

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Potential energy function corresponding to conservative force is given as U ( x , y , z ) = 3 x 2 2 + 5 y + 6 z , then the force at x = 6 is pN. The value of p upto its nearest integral value is

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Potential energy function corresponding to conservative force is given as $U (x, y, z) = \frac{3 x^{2}}{2} + 5 y + 6 z$ , then the force at x = 6 is pN. The value of p upto its nearest integral value is