Statement-I: In aniline, –NH2 group is strong deactivating group for all ESR.
Statement-II: Aniline does not show Friedel-Craft alkylation reaction.
(1) Both statement-l and statement-II are correct
(2) Both statement-l and statement-II are incorrect
(3) Statement-l is correct and statement-II is incorrect
(4) Statement-l is incorrect and statement-Il is correct
Statement-I: In aniline, –NH2 group is strong deactivating group for all ESR.
Statement-II: Aniline does not show Friedel-Craft alkylation reaction.
(1) Both statement-l and statement-II are correct
(2) Both statement-l and statement-II are incorrect
(3) Statement-l is correct and statement-II is incorrect
(4) Statement-l is incorrect and statement-Il is correct
In aniline –NH2 is strong activating group due to presence of lone pair in nitrogen.
Aniline does not show Friedel-Craft alkylation reaction, because anhydrous AlCl3 and aniline form salt together
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