The d-electron configuration of [Fe(H?O)?(NO)]²? and K?[Cr(CN)?] respectively are:
The d-electron configuration of [Fe(H?O)?(NO)]²? and K?[Cr(CN)?] respectively are:
Option 1 - <p>t₂g⁴ e_g² and t₂g³ e_g⁰<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>t₂g⁶ e_g¹ and t₂g³ e_g⁰<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>t₂g⁶ e_g¹ and t₂g² e_g¹<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>t₂g⁵ e_g² and t₂g³ e_g⁰</p>
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Correct Option - 1
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ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
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Chemistry Coordination Compounds 2025
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