The number of moles of KMnO₄ that will be needed to react completely with one mole of oxalate ion in acidic solution is

Option 1 - <math> <mrow> <mfrac> <mrow> <mn>5</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>

Option 2 - <math> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>

Option 3 - <math> <mrow> <mfrac> <mrow> <mn>2</mn> </mrow> <mrow> <mn>5</mn> </mrow> </mfrac> </mrow> </math>

Option 4 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>

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Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

$5 C_{2} O_{4}^{2 -} + 2 M n O_{4}^{-} + 16 H^{+} \to 2 M n^{+} + 8 H_{2} O + 10 C O_{2}$

5 moles of $C_{2} O_{4}^{2 -}$ $_{}_{}^{}$ is needed to reduce 2 moles of $M n O_{4}^{2 -}$ $_{}^{}$

1 mole of $C_{2} O_{4}^{2 -}$ is needed to reduce $\frac{2}{5}$ moles of $M n O_{4}^{2 -}$

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Chemistry Redox Reactions 2025

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The number of moles of KMnO4 that will be needed to react completely with one mole of oxalate ion in acidic solution is

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