The rate of a reaction decreased by 3.555 times when the temperature was changed from 40°C to 30°C. The activation energy (in kJmol⁻¹ ) of the reaction is _____.

 

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5 months ago

log (k? /k? ) = (Ea / 2.303R) [1/T? - 1/T? ]
log (3.555) = (Ea / (2.303R) [1/303 - 1/313]
1.268 * 8.314 * 303 * 313 = 10Ea
So, Ea = 100 kJ

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ΔG° = –RT * 2.303 log K

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Chemistry Chemical Kinetics 2025

Chemistry Chemical Kinetics 2025

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