The stepwise formation of [ C u ( N H 3 ) 4 ] 2 + is given below:

C u 2 + + N H 3 k 1 [ C u ( N H 3 ) ] 2 +

[ C u ( N H 3 ) ] 2 + + N H 3 k 2 [ C u ( N H 3 ) 2 ] 2 +

[ C u ( N H 3 ) 2 ] 2 + + N H 3 k 3 [ C u ( N H 3 ) 3 ] 2 +

[ C u ( N H 3 ) 3 ] 2 + + N H 3 k 4 [ C u ( N H 3 ) 4 ] 2 +            

The value of stability constants k1, k2, k3 and k4 are 1 0 4 , 1 . 5 8 * 1 0 3 , 5 * 1 0 2 a n d 1 0 2  respectively.

The overall equilibrium constants for dissociation of [ C u ( N H 3 ) 4 ] 2 + i s x * 1 0 1 2 .  The value of x is________ (Rounded off to the nearest integer)

5 Views|Posted 5 months ago
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5 months ago

Stability constant are :

K1 = 104

K2 = 1.58 * 103

K3 = 5 * 102

K4 = 102

Overall stability constant K will be

 K = K1 * K2 * K3 * K4

 = 7.9 * 1011

 Now, overall equilibrium constant for dissociation of [Cu (NH3)4]2+ is

K ' = 1 K = 1 7 . 9 * 1 0 1 1 = 0 . 1 2 6 * 1 0 1 1            

= 1.26 * 10-12

So; x = 1 (Rounded off to the nearest integer)

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Chemistry Coordination Compounds 2025

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