Three capacitors each of capacitance C = 2μF are connected with a battery of emf 30V as shown in the figure. When the switch S is closed, the heat generated in circuit will be n/10 mJ. Find the value of n.

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V
5 months ago

Ui = ½C (V/3)² + ½C (V/3)² + ½C (2V/3)²
Uf = ½CV²
Wb = CV²/3
ΔH = [Wb - (Uf - Ui)] = CV²/6 = 0.30 mJ

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Physics Electrostatic Potential and Capacitance 2025

Physics Electrostatic Potential and Capacitance 2025

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