Two satellites A and B of masses 200kg and 400kg are revolving round the earth at height of 600km and 1600km respectively. If T_A and T_B are the time periods of A and B respectively then the value of T_B – T_A :

**[Given : radius of earth = 6400km, mass of earth = 6 * 10²⁴kg]**

Option 1 - 3.33 × 102s

Option 2 - 1.33 × 102s

Option 3 - 4.24 × 102s

Option 4 - 4.24 × 103s

3 Views|Posted 4 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 4

Detailed Solution:

$T = 2 π \sqrt[]{\frac{r^{3}}{G M_{e}}}$

$T_{B} - T_{A} = \frac{2 π}{\sqrt[]{G M_{e}}} (r_{B}^{3 / 2} - r_{A}^{3 / 2}) = \frac{2 * 3.14}{\sqrt[]{6.67 * 1 0^{- 11} * 6 * 1 0^{24}}} [{(8 * 1 0^{6})}^{\frac{3}{2}} - {(7 * 1 0^{6})}^{\frac{3}{2}}]$

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Two satellites A and B of masses 200kg and 400kg are revolving round the earth at height of 600km and 1600km respectively. If TA and TB are the time periods of A and B respectively then the value of TB – TA : [Given : radius of earth = 6400km, mass of earth = 6 * 1024kg]

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