0.16g of an organic compound gave 0.094g of AgBr by Carius method. The percentage of Br in the compound is (Atomic mass of Ag = 108 u, Br = 80 u)

CuSO₄ acts as catalyst in Kjeldahl's method of estimation of nitrogen.

  $N{H}_4^{+}$  does not have vacant orbitals, therefore it cannot behave as electrophile.

Number of moles of C = Number of moles of CO₂ = $\frac{330}{44}$ moles

Number of moles of H = 2 × no. of moles of H₂O = $\left(\frac{270}{18}\times 2\right)$ moles

 Mass of C = $\frac{330}{44}\times 12$ gm = 90 gm

 Mass of H = $\frac{270}{18}\times 2\times 1gm=30gm$

$\begin{array}{l}\mathrm{\%}ofC=\frac{90}{120}\times 100\mathrm{\%}=75\mathrm{\%}\\ \mathrm{\%}ofH=\frac{30}{120}\times 100\mathrm{\%}=25\mathrm{\%}\end{array}$