1.15 A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?
1.15 A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?
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1 Answer
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1.15 Number of atoms in close packaging = 0.5 mol
1 atom has 6.022*1023 particles
So Number of particles in close-packed = 0.5 * 6.022 * 1023 = 3.011*1023
Number of tetrahedral voids = 2 * number of atoms in close packaging
Number of tetrahedral voids = 2 * 3.011 * 1023= 6.022*1023
Number of octahedral voids = number of atoms in close packaging
So the number of octahedral voids = 3.011 * 1023
Total number of voids = Tetrahedral void + octahedral void
=6.022 * 1023 + 3.011 * 1023= 9.03*1023
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