1.24. Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: 

N₂ (g) + 3H₂(g) —–> 2NH₃ (g)

(i) Calculate the mass of ammonia produced if 2.00 × 10³ g dinitrogen reacts with 1.00 ×10³ g of dihydrogen.

(ii) Will any of the two reactants remain unreacted?

(iii) If yes, which one and what would be its mass?   

<p><strong>1.24.&nbsp;</strong>According to the given equation, 1 mol of N₂ reacts with 3 mol of H₂.</p><p>Or, 28 g of N₂ react with 6 g of H₂.</p><p>So, 2000 g of N₂ will react with H₂= 6/28 x 2000 g = 428.6 g of H₂.</p><p><strong> (i)</strong> 2 mol of N₂ or 28 g of N₂ produce NH₃ = 2 mol = 34 g</p><p>So, 2000 g of N₂ will produce NH₃ = 34/28 x 2000 g = 2428.57 g</p><p><strong> (ii)</strong> Yes, N₂ is the limiting reagent while H₂ is the excess reagent. So, H₂will remain unreacted.</p><p><strong> (iii)</strong> H₂ will remain unreacted. Mass left unreacted = 1000 g – 428.6 g = 571.4 g</p>

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