1.24. Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2 (g) + 3H2(g) —–> 2NH3 (g)
(i) Calculate the mass of ammonia produced if 2.00 * 103 g dinitrogen reacts with 1.00 *103 g of dihydrogen.
(ii) Will any of the two reactants remain unreacted?
(iii) If yes, which one and what would be its mass?
1.24. Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2 (g) + 3H2(g) —–> 2NH3 (g)
(i) Calculate the mass of ammonia produced if 2.00 * 103 g dinitrogen reacts with 1.00 *103 g of dihydrogen.
(ii) Will any of the two reactants remain unreacted?
(iii) If yes, which one and what would be its mass?
1.24. According to the given equation, 1 mol of N2 reacts with 3 mol of H2.
Or, 28 g of N2 react with 6 g of H2.
So, 2000 g of N2 will react with H2 = 6/28 x 2000 g = 428.6 g of H2.
(i) 2 mol of N2 or 28 g of N2 produce NH3 = 2 mol = 34 g
So, 2000 g of N2 will produce NH3 = 34/28 x 2000 g = 2428.57
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