1.3. Determine the empirical formula of an oxide of iron, which has 69.9% iron and 30.1 % dioxygen by mass.
1.3. Determine the empirical formula of an oxide of iron, which has 69.9% iron and 30.1 % dioxygen by mass.
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1 Answer
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1.3 We are given that the percentage of iron by mass is 69.9% and the percentage of oxygen by mass is 30.1%.
Since we have relative moles of both elements, we can calculate the simpler molar ratio of iron to oxygen
= 1.25: 1.88
Divide by the smaller value to both
= 1.25/1.25: 1.88/1.25
= 1: 1.5
= 2: 3
So, now we can write the empirical formula of iron oxide as Fe2O3.
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