1.3. Determine the empirical formula of an oxide of iron, which has 69.9% iron and 30.1 % dioxygen by mass.

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9 months ago

1.3 We are given that the percentage of iron by mass is 69.9% and the percentage of oxygen by mass is 30.1%.

Since we have relative moles of both elements, we can calculate the simpler molar ratio of iron to oxygen

= 1.25: 1.88

Divide by the smaller value to both

= 1.25/1.25: 1.88/1.25

= 1: 1.5

= 2: 3

So,

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