1.4. Calculate the amount of carbon dioxide that could be produced when
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen. 

<p><strong>1.4 </strong>In order to answer the question, we need to know the balanced equation for the combustion of carbon in dioxygen/air, which can be written as:</p><p>C (s) + O₂ (g) à CO₂ (g)</p><p><strong> (i)</strong> We can see from the above equation, </p><p>1 mole of carbon reacts with 1 mole of oxygen to produce 1 mol of carbon dioxide.</p><p>In air, combustion is complete.</p><p>Therefore, CO₂produced from combustion of 1 mole of carbon= Molar mass of CO₂= 44 g</p><p><strong> (ii)</strong> As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant.</p><p>Hence, CO₂_&nbsp;produced = 22 g</p><p>Here, dioxygen acts as the limiting reagent.</p><p><strong> (iii)</strong> Here again, dioxygen is the limiting reactant.</p><p>16 g of dioxygen can combine only with 0.5 mole of carbon (even though 2 moles of carbon are available). Therefore, the CO₂&nbsp;produced again is equal to 22 g.</p>

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