1.45 Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?
1.45 Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?
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1 Answer
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1.45 For fcc unit cell, a=2√2?.
Here, a is the edge length and r is the atomic radius (0.144 nm).
a = 2√2 ×0.144 = 0.407 nm
Hence, the length of a side of a cell is 0.407 nm.
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