10.0 ml of 0.05 M KMnO₄ solution was consumed in a titration with 10.0 mL of given oxalic acid dehydrate solution. The strength of given oxalic acid solution is _____ *10⁻² g/L. (Round off to the Nearest Integer).
10.0 ml of 0.05 M KMnO₄ solution was consumed in a titration with 10.0 mL of given oxalic acid dehydrate solution. The strength of given oxalic acid solution is _____ *10⁻² g/L. (Round off to the Nearest Integer).
MnO? + H? C? O?2H? O - (H? )-> Mn²? + CO?
nf = (5) nf = (2)
Milli equivalent of C? O? ²? = mili equivalent of MnO?
2 x M x 10 = 5 x 0.05 x 10
M = 0.125 M
M = Strength / M.M of H? C? O?2H? O
Strength = 0.125 x 126g/L
= 15.75g/L
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eight 2025
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