11.13. Rationalise the given statements and give chemical reactions: Lead (II) chloride reacts with Cl2 to give PbCl4. Lead (IV) chloride is highly unstable towards heat. Lead is known not to form an iodide PbI4.

PbCl2 + Cl2→ PbCl4. This is because Pb can show +2 oxidation state more easily than +4 due to inert pair effect. PbCl4→ PbCl2 + Cl2 Because Pb2+ is more stable than Pb4+ due to inert pair effect. PbI4does not exist because I- ion being a powerful reducing agent reduces Pb4+ ion to Pb2+ ion in solution. Pb4+ + 2I– → Pb2+ + I2

11.13.

Rationalise the given statements and give chemical reactions:

Lead (II) chloride reacts with Cl₂to give PbCl₄.

Lead (IV) chloride is highly unstable towards heat.

Lead is known not to form an iodide PbI₄.

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Vishal Baghel | Contributor-Level 10

9 months ago

PbCl₂+ Cl₂→ PbCl₄.
This is because Pb can show +2 oxidation state more easily than +4 due to inert pair effect.
PbCl₄→ PbCl₂ + Cl₂
Because Pb²⁺ is more stable than Pb⁴⁺ due to inert pair effect.
PbI₄does not exist because I^- ion being a powerful reducing agent reduces Pb⁴⁺ ion to Pb²⁺ ion in solution.