11.15

(i) Draw the structures of all isomeric alcohols of molecular formula C₅H₁₂O and give their IUPAC names.

(ii) Classify the isomers of alcohols in question 11.3 (i) as primary, secondary and tertiary alcohols.

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alok kumar singh | Contributor-Level 10

5 months ago

11.15

The structures of all isomeric alcohols of C₅H₁₂O are given below:

Naming is done by the conventional method. The -OH group is attached on the first carbon.

(b) 3-Methylbutan-1-ol

Butane is the longest chain and methyl is the substituent group.

(c) 3-Methylbutan-1-ol

the longest chain is butane and conventional naming method is used.

(d) 2,2-Dimethylpropan-1-ol

Isomer is made by transforming the principal carbon into tertiary type. The longest chain is butane and named accordingly.

(e) Pentan-2-ol

the longest chain is pentane and the numbering is chosen from the minimum position.

Butane is the longest chain, further numbering is done b

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11.15 The structures of all isomeric alcohols of C5H12O are given below:Naming is done by the conventional method. The -OH group is attached on the first carbon. (b) 3-Methylbutan-1-olButane is the longest chain and methyl is the substituent group. (c) 3-Methylbutan-1-olthe longest chain is butane and conventional naming method is used. (d) 2,2-Dimethylpropan-1-olIsomer is made by transforming the principal carbon into tertiary type. The longest chain is butane and named accordingly. (e) Pentan-2-olthe longest chain is pentane and the numbering is chosen from the minimum position.Butane is the longest chain, further numbering is done by choosing a minimum position for the-OH group followed by other substituents. (g) Pentan-3-olConventional method of naming is used. (h) 2-Methylbutan-2-olButane is the longest chain and substituents are named accordingly by looking into minimum position. (f) 3-Methylbutan-2-olButane is the longest chain, further numbering is done by choosing a minimum position for the-OH group followed by other substituents. (g) Pentan-3-olConventional method of naming is used. (h) 2-Methylbutan-2-olButane is the longest chain and substituents are named accordingly by looking into minimum position.<table><tbody><tr><td width="302">  (A) Primary alcohol</td><td width="255">  Explanation</td></tr><tr><td width="302">   (i)  Pentan-1-ol   (ii)  2-Methylbutan-1-ol   (iii)  3-Methylbutan-1-ol   (iv)  2,2-Dimethylpropan-1-ol</td><td width="255">  The -OH group is attached to the carbon that is attached to another single carbon.</td></tr><tr><td width="302">   (B) Secondary alcohol</td><td width="255"> </td></tr></tbody></table><table><tbody><tr><td width="302">  (i)  Pentan-2-ol   (ii)  3-Methylbutan-2-ol   (iii)  Pentan-3-ol</td><td width="255"> The -OH group is attached to the carbon that is attached to another two carbons.</td></tr><tr><td width="302">   (C) Secondary alcohol</td><td width="255"> </td></tr><tr><td width="302">   (i) 2-Methylbutan-2-ol</td><td width="255">  The -OH group is attached to the carbon group that is further attached to another three carbon atoms.</td></tr></tbody></table>