13.3 How will you convert
(i) Benzene into aniline
(ii) Benzene into N, N-dimethylaniline
(iii) Cl–(CH2)4–Cl into hexan-1,6-diamine?
13.3 How will you convert
(i) Benzene into aniline
(ii) Benzene into N, N-dimethylaniline
(iii) Cl–(CH2)4–Cl into hexan-1,6-diamine?
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1 Answer
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Benzene into aniline
When Benzene is treated with HNO3/H2SO4 it forms nitrobenzene. When Nitrobenzene reduced with Sn/HCL it forms Aniline because Sn/HCl is a reducing Mixture.
When Benzene is reacted with nitrating mixture it forms nitrobenzene. When it Reduced H2/Pd in ethanol or Sn/HCl, it forms Aniline. When Aniline reacts 2 times with CH3Cl It forms N, N- dimethylaniline.
When 1,4-dichlorobutane reacts with NaCN it forms Di cyanide compound, After Hydrogenation it forms the Hexane 1,6-Diamine.
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