14. Calculate the standard enthalpy of formation of CH3OH from the following data:
(i) CH3OH(l) + 3/2 O2 (g) → CO2 (g) + 2H2O (l); ?rH?= – 726kJ mol-1
(ii) C(graphite) + O2(g) → CO2 (g); ?cH? = – 393 kJ mol-1
(iii) H2(g) + 1/2O2(g) → H2O (l); ?fH? = -286 kJ mol-1
14. Calculate the standard enthalpy of formation of CH3OH from the following data:
(i) CH3OH(l) + 3/2 O2 (g) → CO2 (g) + 2H2O (l); ?rH?= – 726kJ mol-1
(ii) C(graphite) + O2(g) → CO2 (g); ?cH? = – 393 kJ mol-1
(iii) H2(g) + 1/2O2(g) → H2O (l); ?fH? = -286 kJ mol-1
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1 Answer
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14. The reaction for the formation of CH3OH can be obtained by:
C (s) + 2H2 (g) + l/2O2 (g) → CH3OH (l)
This can be obtained by the algebraic calculations of the reactions:
Equation (ii) + 2 x equation (iii) – equation (i)
? Hf [CH3OH] =? cH? + 2 x? fH? -? rH?
= (– 393 kJ mol-1) + 2 (- 286 kJ mol-1) – (– 726 kJ mol-1)
= (–
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