15. Calculate the enthalpy change for the process
CCl4(g) → C(g) + 4 Cl(g)
and calculate bond enthalpy of C – Cl in CCl4(g).
ΔvapH?(CCl4) = 30.5 kJ mol–1.
ΔfH? (CCl4) = –135.5 kJ mol–1.
ΔaH? (C) = 715.0 kJ mol–1, where ΔaH? is enthalpy of atomisation
ΔaH? (Cl2) = 242 kJ mol–1
15. Calculate the enthalpy change for the process
CCl4(g) → C(g) + 4 Cl(g)
and calculate bond enthalpy of C – Cl in CCl4(g).
ΔvapH?(CCl4) = 30.5 kJ mol–1.
ΔfH? (CCl4) = –135.5 kJ mol–1.
ΔaH? (C) = 715.0 kJ mol–1, where ΔaH? is enthalpy of atomisation
ΔaH? (Cl2) = 242 kJ mol–1
15. According to the question:
i. CCl4 (l) → CCl4 (g), ? vapH? = 30.5 kJ mol–1
iii. C (s) + 2Cl2 (g) → CCl4 (l), ? fH? = –135.5 kJ mol–1
iii. C (s) → C (g), ? aH? = 715.0 kJ mol–1
iv Cl2 (g) → C (g) + 4 Cl (g) ? aH
Similar Questions for you
Kindly go through the solution
(1) [Ni (NH3)6]+2 → Ni+2 → d8, C. No. = 6,
SP3d2, Para
(2) [Co (H2O)6]+2 → Co+2 → d6, C. No. = 6
d2sp3, Dia
(3) [Ti (H2O)6]+3 → Ti+3 → d1, C. No. = 6
d2SP3, Para
(4) [Co (NH3)6]+3 → Co+3 → d5, C. No. = 6
d2sp3, Para
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry Ncert Solutions Class 11th 2023
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering


