2L of 0.2 M H2SO4 is reacted with 2L of 0.1 M NaOH solution, the molarity of the resulting product Na2SO4 in the solution is_________ millimolar (Nearest integer)

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Chemistry Class 12th Some Basic Concepts of Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter One

2L of 0.2 M H₂SO₄ is reacted with 2L of 0.1 M NaOH solution, the molarity of the resulting product Na₂SO₄ in the solution is_________ millimolar (Nearest integer)

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Vishal Baghel | Contributor-Level 10

2 months ago

H₂SO₄ + 2NaOH -> Na₂SO₄ + 2H₂O

Number of mole = 0.2 × 2 2 × 0.1 - -

0.4 = 0.2

No. of moles after reaction = 0.4 – 0.1 0.2 – 0.2 &n

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H₂SO₄ + 2NaOH -> Na₂SO₄ + 2H₂O

Number of mole = 0.2 × 2 2 × 0.1 - -

0.4 = 0.2

No. of moles after reaction = 0.4 – 0.1 0.2 – 0.2 0.1

= 0.3 = 0

molarity of Na₂SO₄ = $\frac{n}{V (L)} = \frac{0.1}{4} = 0.025$

$∴$ = 25 milli molar

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2L of 0.2 M H₂SO₄ is reacted with 2L of 0.1 M NaOH solution, the molarity of the resulting product Na₂SO₄ in the solution is_________ millimolar (Nearest integer)

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