2O₃(g) $?$ 3O₂(g)

At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)________. J mol^?1. (Nearest integer)

[Given: In 1.35 = 0.3 and R=8.3 J K^-1 mol^-1]

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Vishal Baghel | Contributor-Level 10

2 months ago

2O₃(g) -> 3O₂

t = 0 a moles 0

-0.5a mole +0.75a mole

At Eq. 0.5a mole 0.75a mole

Total moles at eq = 0.5a + 0.75 a = 1.25a

$P_{O_{3}} = x_{O_{3}} \times P_{T} = \frac{0.5 a}{1.25 a} \times 1 = \frac{2}{5} a t m$

$P_{O_{2}} = x_{O_{2}} \times p_{T} = \frac{0.75 a}{1.25 a} \times 1 = \frac{3}{5} a t m$

$K_{p} = \frac{{(P_{O_{2}})}_{e q}^{3}}{{(P_{O_{3}})}_{e q}^{3}} = \frac{{(\frac{3}{5})}^{3}}{{(2 / 5)}^{2}} = 1.35 a t m$

$Δ G^{°} = - R T l n K P$

$\begin{array}{l} = - 8.3 \times 300 l n 1.35 \\ = - 747 J / m o l e \end{array}$

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2O₃(g) $?$ 3O₂(g)

At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)________. J mol^?1. (Nearest integer)

[Given: In 1.35 = 0.3 and R=8.3 J K^-1 mol^-1]

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2O3(g) ? 3O2(g) At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)________. J mol?1. (Nearest integer) [Given: In 1.35 = 0.3 and R=8.3 J K-1 mol-1]

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2O₃(g) $?$ 3O₂(g)

At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)________. J mol^?1. (Nearest integer)

[Given: In 1.35 = 0.3 and R=8.3 J K^-1 mol^-1]