34. Which of the following is the correct IUPAC name?
(i) 3-Ethyl-4, 4-dimethylheptane
(ii) 4,4-Dimethyl-3-ethylheptane
(iii) 5-Ethyl-4, 4-dimethylheptane
(iv) 4,4-Bis(methyl)-3-ethylheptane
34. Which of the following is the correct IUPAC name?
(i) 3-Ethyl-4, 4-dimethylheptane
(ii) 4,4-Dimethyl-3-ethylheptane
(iii) 5-Ethyl-4, 4-dimethylheptane
(iv) 4,4-Bis(methyl)-3-ethylheptane
-
1 Answer
-
This is a Multiple Choice Questions as classified in NCERT Exemplar
34. Option (i) 3-Ethyl-4, 4-dimethylheptane is correct since in IUPAC naming the different alkyl groups present are written in alphabetical order. Di, tri, tetra are not included in the alphabetical order. So, “e” of the ethyl group comes before the “m” of the dimethyl group. The number 3 is given to the ethyl group and is written first.
Similar Questions for you
This is a Assertion Type Questions as classified in NCERT Exemplar
65. Option (i)
i.e., Both A and R are correct, and R is the correct explanation of A is the answer since in paper chromatography, a special quality of paper known as chromatography paper is used. Chromatography paper contains water molecules trapped in it which acts as the stationary phase. A strip of chromatography paper spotted at the base with the solution of the mixture is suspended in a suitable solvent or a mixture of solvents which acts as the mobile phase. The solvent rises up the paper by capillary action and flows over the spot. The paper selectively
This is a Assertion Type Questions as classified in NCERT Exemplar
64. Option (iii) i.e., Both A and R are not correct is the answer since sulphur is estimated by Carius method in the form of white precipitate of BaSO4 on heating with fuming and BaCl2. If light yellow solid is obtained means impurities are present. It is filtered, washed and then dried to get pure BaSO4 .
This is a Assertion Type Questions as classified in NCERT Exemplar
63. Option (iv) i.e., A is not correct, but R is correct is the answer since hybridization of C can be found out by counting σ bonds and π bonds present on C atom. This can be shown as-
If C has 3σ bonds then it is sp2 hybridized. If C has 2σ bonds then it is sp hybridized.
This is a Assertion Type Questions as classified in NCERT Exemplar
62. Option (i) i.e.,
Both A and R are correct, and R is the correct explanation of A is the answer as when two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are known as position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because they differ in the position of the double bond.
This is a Assertion Type Questions as classified in NCERT Exemplar
61. Option (iv)
i.e., A is not correct, but R is correct is the answer. This is because canonical structures always have more energy than the resonance hybrid. Resonance hybrids are always found to be more stable than any of the canonical structures since the delocalization of electrons lowers the orbitals energy and gives stability.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers