4.11 For the reaction 2A + B → A2B the rate = k[A][B]2 with k = 2.0 * 10–6 mol–2 L2 s–1. Calculate the initial rate of the reaction when [A] = 0.1 mol L–1, [B] = 0.2 mol L–1. Calculate the rate of reaction after [A] is reduced to 0.06 mol L–1.
4.11 For the reaction 2A + B → A2B the rate = k[A][B]2 with k = 2.0 * 10–6 mol–2 L2 s–1. Calculate the initial rate of the reaction when [A] = 0.1 mol L–1, [B] = 0.2 mol L–1. Calculate the rate of reaction after [A] is reduced to 0.06 mol L–1.
4.11 (a) Rate = k [A] [B]2, Rate = 0 * 10-6 [0.1] [0.2]2
Rate = 8 * 10-9 mol L-1sec-1
(b) 2A +B = A2B
=0.06+ 0.18 = 0.02
Situation when A remains 0.06 mol L-1
Now, According to rate law, Rate = k [A] [B]2
Rate = 2 * 10-6 [0.06] [0.18]2
i.e. Rate = 3.888 * 10-9 mol L-1sec-1
Initial rate of reaction is 8 * 1
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Chemistry Ncert Solutions Class 12th 2023
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