4.17 In a pseudo first order hydrolysis of ester in water, the following results were obtained, Calculate the average rate of reaction between the time intervals 30 to 60 seconds.
t/s
0
30
60
90
[Ester]/mol L-1
0.55
0.31
0.17
0.085
4.17 In a pseudo first order hydrolysis of ester in water, the following results were obtained, Calculate the average rate of reaction between the time intervals 30 to 60 seconds.
|
t/s |
0 |
30 |
60 |
90 |
|
[Ester]/mol L-1 |
0.55 |
0.31 |
0.17 |
0.085 |
-
1 Answer
-
4.17 (i) Average rate of reaction over interval is [change in concentration]/ [time taken] e.
[0.31 - 0.17] / [60-30] = 0.00467 mol L-1 sec-1
(ii) the pseudo first-order rate constant can be calculated by K = (2.303/t) log (Ci/Ct)
where K is Rate constant,
t is time taken,
Ci is initial concentration
Ct is Concentration at time t.
K = (2.303/30) log (0.55/0.31)
? K = 1.9 * 10-2 sec-1
(i) Average rate between 30 to 60 sec is 0.00467 mol L-1sec-1
(ii) Pseudo first order rate constant is 1.* 10-2sec-1
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