4.18 A reaction is first order in A and second order in B.

(i) Write the differential rate equation.

(ii) How is the rate affected on increasing the concentration of B three times?

(iii) How is the rate affected when the concentrations of both A and B are doubled? 

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    Answered by

    Payal Gupta | Contributor-Level 10

    5 months ago

    4.18  (i) Order is power raised to reactant in rate law, hence,

    Rate = k [A] [B]2

    (ii) When the concentration of B is increased three times then the rate is affected by the square of The rate is increased by 9 Times.

    (iii) When the concentration of reactant both A and B is doubled then the rate will have affected as square of reactant B and Two times of Reactant Overall increase in rate is 8 times

    (a) When the concentration of B is increased by three times, the rate is increased by nine times

    (b) When of both reactants is doubled, the Rate increases 8 times.

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