4.21 The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
Experiment
[A]/mol L-1
[B]/mol L-1
Initial rate/mol L-1 min-1
I
0.1
0.1
2.0 × 10-2
II
-
0.2
4.0 × 10-2
III
0.4
0.4
-
IV
-
0.2
2.0 × 10-2
4.21 The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
Experiment |
[A]/mol L-1 |
[B]/mol L-1 |
Initial rate/mol L-1 min-1 |
I |
0.1 |
0.1 |
2.0 × 10-2 |
II |
- |
0.2 |
4.0 × 10-2 |
III |
0.4 |
0.4 |
- |
IV |
- |
0.2 |
2.0 × 10-2 |
-
1 Answer
-
4.21 As reaction is first order with respect to A and zero Order with respect to B. Then changing the concentration of B won't affect the rate of reaction and increasing concentration of A 'n' times will increase the rate by 'n' times. By this logic lets fill the table- In first blank space concentration of A will be 0.2 mol L-1 because the rate is doubled. In second blank space, Rate will be 8 * 10-2mol L-1min-1 because the concentration of A is increased 4 Times. In third blank space concentration of A will be 0.1 mol L-1 because the rate is same as in experiment I.
Experiment
[A]/mol L-1
[B]/mol L-1
Initial rate/mol L-1 min-1
I
0.1
0.1
2.0 * 10-2
II
0.2
0.2
4.0 * 10-2
III
0.4
0.4
8.0 * 10-2
IV
0.1
0.2
2.0 * 10-2
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