4.22 Calculate the half-life of a first order reaction from their rate constants given below: (i) 200 s–1 (ii) 2 min–1 (iii) 4 years–1
4.22 Calculate the half-life of a first order reaction from their rate constants given below: (i) 200 s–1 (ii) 2 min–1 (iii) 4 years–1
-
1 Answer
-
4.22 Half life of first order reaction is, t1/2 = ln2/K where t1/2 is half life of first order reaction, K is rate constant of First order reaction.
(i) t1/2 = ln2/200 s-1
⇒t1/2 = 0.693/200 s-1 (? ln2 = 0.693)
⇒t1/2 = 0.003465 sec.
(ii) t1/2 = ln2/2 min-1
⇒t1/2 = 0.693/2 min-1 (? ln2 = 0.693)
⇒t1/2 = 0.3465 min
(iii) t1/2 = ln2/4 year-1
⇒t1/2 = 0.693/4 years -1 (? ln2 = 0.693)
⇒t1/2 = 0.17325 year.
Half life of 3 reactions are 0.003465 sec, 0.3465 min, 0.17325 year, respectively.
Similar Questions for you
Kindly go through the solution
Ea = 216.164kJ/mol 216
Reaction rate is used to measure how fast or slow reactions occur per unit time. The rate constant is a proportionality factor that remains constant for every reaction.
Yes, in elementary reactions, order and molecularity can be the same, but this is not always the case because order is an experimental quantity, and molecularity is a theoretical concept.
Reaction Kinetics, also known as chemical kinetics, is the study of the rate of chemical reaction and the factors affecting the reaction rate, such as temperature, concentration, and catalyst.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers