4.23 The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
4.23 The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
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2 Answers
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4.23 Radio active decay occurs via first order rate law,
t1/2 = 5730 years. rate constant (k) of given decay is 0.693/t1/2
⇒0.693/5730 = 1.2 × 10-4 year-1
By first order integrated rate law age of the sample will be,
T = ( 2.303 / 1.2 X 10-4 ) log (A0/At)
where T is the age of the sample, A0 is the initial activity of the sample. and At is the activity of the sample at any time t
T = ( 2.303 / 1.2 X 10-4 ) log (A0/0.8 A0)
T = 0.18 × 104 years.
Age of given sample is 0.18 × 104 years.
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4.23 Radio active decay occurs via first order rate law,
t1/2 = 5730 years. rate constant (k) of given decay is 0.693/t1/2
?0.693/5730 = 1.2 * 10-4 year-1
By first order integrated rate law age of the sample will be,
T = ( 2.303 / 1.2 X 10-4 ) log (A0/At)
where T is the age of the sample, A0 is the initial activity of the sample. and At is the activity of the sample at any time t
T = ( 2.303 / 1.2 X 10-4 ) log (A0/0.8 A0)
T = 0.18 * 104 years.
Age of given sample is 0.18 * 104 years.
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