4.24 The experimental data for decomposition of N2O5 [2N2O5 → 4NO2 + O2 ] in gas phase at 318K are given below:
(i) Plot [N2O5 ] against t.
(ii) Find the half-life period for the reaction.
(iii) Draw a graph between log[N2O5 ] and t.
(iv) What is the rate law ?
(v) Calculate the rate constant.
(vi) Calculate the half-life period from k and compare it with (ii).
t/s
0
400
800
1200
1600
2000
2400
2800
3200
102 ×
[N2O5]/mol L-1
1.63
1.36
1.14
0.93
0.78
0.64
0.53
0.43
0.35
4.24 The experimental data for decomposition of N2O5 [2N2O5 → 4NO2 + O2 ] in gas phase at 318K are given below:
(i) Plot [N2O5 ] against t.
(ii) Find the half-life period for the reaction.
(iii) Draw a graph between log[N2O5 ] and t.
(iv) What is the rate law ?
(v) Calculate the rate constant.
(vi) Calculate the half-life period from k and compare it with (ii).
t/s |
0 |
400 |
800 |
1200 |
1600 |
2000 |
2400 |
2800 |
3200 |
102 × [N2O5]/mol L-1 |
1.63 |
1.36 |
1.14 |
0.93 |
0.78 |
0.64 |
0.53 |
0.43 |
0.35 |
-
1 Answer
-
4.24
(iv) As log [N2O5] vs time is a straight line given reaction is first Hence its rate law will be, Rate = k [N2O5]
(v) The slope of above graph is slope = 0.000209 K = 303 × slope
⇒4.82 × 10-4sec-1
Now, t1/2 = 0.693/K.
⇒0.693/4.82 × 10-4
⇒t1/2 = 1438 sec. which is almost equal to (ii)
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