4.26 During nuclear explosion, one of the products is 90 Sr with half-life of 28.1 years. If 1µg of 90Sr was absorbed in the bones of a newly born baby instead of calcium, how much of it will remain after 10 years and 60 years if it is not lost metabolically?
4.26 During nuclear explosion, one of the products is 90 Sr with half-life of 28.1 years. If 1µg of 90Sr was absorbed in the bones of a newly born baby instead of calcium, how much of it will remain after 10 years and 60 years if it is not lost metabolically?
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1 Answer
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4.26 Initial concentration, [R]° = 1? g
Final concentration, [R] Half-life t1/2 = 28.1 years Solution:
We know, t1/2 = 0.693/k Where, k – rate constant
? k = 0.693/ t1/2
? k = 0.693/ (28.1 yrs)
? k = 0.0246 yrs-1
Also, t = 2.303 / k log R0 / R
If t = 10yrs, then, using the formula, we get,
t = 2.303 / k log R0 / R
10 = 2.303 / 0.0246 log 1 / R10
log 1 / R10 = 0.0246 X 10 / 2.303
log 1 / R10 = 0.246 / 2.303
1 / R10 = antilog (0.246 / 2.303)
1 / R10 = 1.278
? R10 = 0.7824? g
If t = 60yrs, then again, we get,
60 = 2.303 / 0.0246 log 1 / R60
log 1 / R60 = 0.0246 X 60 / 2.303
log 1 / R60 =
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