4.28 A first order reaction takes 40 min for 30% decomposition. Calculate t1/2.
4.28 A first order reaction takes 40 min for 30% decomposition. Calculate t1/2.
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1 Answer
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4.28 Given:
Time t = 40 min
When 30% decomposition is undergone, 70% is the concentration.
We know, time taken
t= 2.303/K log R0 / R
Where, k- rate constant
[R]0 - initial concentration
[R] - concentration at time 't'
40 = 2.303/K log R0 / 0.7 R0
40 = 2.303/K log 1 / 0.7
40 / 0.1549 = 2.303 / k
?258.23 = (2.303/k)
We know, Half-life t1/2 = 0.693/k
Which can be written as, t1/2 = 0.3010 * (2.303/k)
? t1/2 = 0.3010 * 258.23
? t1/2 = 77.72 min
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