4.4 The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?
4.4 The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?
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1 Answer
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4.4 Let the reaction be X→Y
As this reaction follows second order kinetics, the rate of the reaction will be,
Rate = k (X)2 → Equation 1
Since the concentration of X is increased three times, Equation 1 will become,
Rate = k (3X)2
= k × 9 (X)2
∴ The rate of formation of Y will become 9 times.
Thus, the rate of formation of Y will become 9 times
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