4.8 The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea .
4.8 The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea .
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1 Answer
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4.8 Given-
Initial temperature, T1 = 298 K
Final temperature, T2 = 298 K + 10 K = 308 K
Knowing that the rate constant of a chemical reaction normally increases with increase in temperature, we assume that,
Initial value of rate constant, k1 = k
Final value of rate constant, k2 = 2k
Using Arrhenius equation,
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Ea = 216.164kJ/mol 216
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