47. Highest oxidation state of manganese in fluoride is +4 (MnF4)but highest oxidation state in oxides is +7 (Mn2O7) because
(A) Fluorine is more electronegative than oxygen
(B) Fluorine does not possess d-orbitals
(C) Fluorine stabilizes lower oxidation state
(D) In covalent compounds fluorine can form single bond only while oxygen forms double bond
47. Highest oxidation state of manganese in fluoride is +4 (MnF4)but highest oxidation state in oxides is +7 (Mn2O7) because
(A) Fluorine is more electronegative than oxygen
(B) Fluorine does not possess d-orbitals
(C) Fluorine stabilizes lower oxidation state
(D) In covalent compounds fluorine can form single bond only while oxygen forms double bond
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1 Answer
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47. (D) in covalent compounds fluorine can form single bond only while oxygen forms double bond
Oxygen has the capacity to form multiple bonds which enables it to form a variety of covalent compounds.
In (Mn2O7) also, 6 oxygen are doubly bonded to two manganese atoms and one oxygen is forming bridge between two.
While in (MnF4), four fluorine atoms are singly bonded to manganese atom giving it a +4 oxidation state.
Therefore, due to capability of oxygen to have multiple bonds in covalent compounds, manganese is having higher oxidation state of +7 in (Mn2O7) .
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