5.1. What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?

5.1. Initial Pressure, P1 = 1 bar Final Pressure, P2 =? Initial Volume, V1= 500 dm3 Final Volume, V2=200 dm3 As the value of temperature constant (=30°C) P1V1=P2V2 1 bar x 500 dm3 = P2 x 200 dm3 Or P2=500/200 bar =2.5 bar = mRT/MV Replacing m/V by d (i.e. density), we get P = dRT/M P? d Hence, at a given temperature, the density of a gas is directly proportional to its pressure.

5.1. What will be the minimum pressure required to compress 500 dm³ of air at 1 bar to 200 dm³ at 30°C?

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Payal Gupta | Contributor-Level 10

8 months ago

5.1. Initial Pressure, P₁ = 1 bar Final Pressure, P₂ =?

Initial Volume, V₁= 500 dm³ Final Volume, V₂=200 dm³
As the value of temperature constant (=30°C)
P₁V₁=P₂V₂
1 bar x 500 dm³ = P₂ x 200 dm³

Or P

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