5.12. Calculate the temperature of 4.0 moles of a gas occupying 5 dm3 at 3.32 bar (R = 0.083 bar dm3 K-1 mol-1).

5.12. Given, P= 3.32 barV= 5 dm3 n= 4 molR= 0.083 bar dm3 K-1 mol-1PV = nRTOr T = PV / nR = 3.32 x 5 dm3 / (4.0 mol x 0.083 bar dm3 K-1 mol-1) = 50 K

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States of Matter Ncert Solutions Chemistry Class 11th Chemistry Class 11th States of Matter

5.12. Calculate the temperature of 4.0 moles of a gas occupying 5 dm³ at 3.32 bar (R = 0.083 bar dm³ K^-1 mol^-1).

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Answered by

Payal Gupta | Contributor-Level 10

5 months ago

5.12. Given,

P= 3.32 bar

V= 5 dm³

n= 4 mol

R= 0.083 bar dm³ K^-1 mol^-1

PV = nRT

Or T = PV / nR = 3.32 x 5 dm³ / (4.0 mol x 0.083 bar dm³ K^-1 mol^-1)

= 50 K

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