5.13. Calculate the total number of electrons present in 1.4 g of dinitrogen gas.
5.13. Calculate the total number of electrons present in 1.4 g of dinitrogen gas.
5.13. Molecular mass of N2 = 28g
28 g of N2 has No. of molecules = 6.022 x 1023
1.4 g of N2 has No. of molecules = (6.022 x 1023 x 1.4 g)/28 g= 3.011 x 1022 molecules.
Atomic No. of Nitrogen (N) = 7
1 molecule of N2 has electrons = 7 x 2 = 14
3.011 x 1022 molecules of N2 have electrons= 14 x 3.011 x 102
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