5.7. What will be the pressure exerted by a mixture of 3.2g of methane and 4.4g of carbon dioxide contained in a 9 dm³ flask at 27 °C?

<p><strong>5.7.&nbsp;</strong>Applying PV = nRT</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; We get P = nRT / V</p><p>Given:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;n_CH4 = 3.2 / 16 mol = 0.2 mol</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;n_CO2= 4.4 /44 mol = 0.1 mol</p><p>So, </p><p>P_CH4= (0.2 mol) (0.0821 dm³atm K^-1 mol^-1) (300 K) / (9 dm³)</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = 0.55 atm</p><p>&nbsp;P_CO2= (0.1 mol) (0.0821 dm³atm K^-1 mol^-1) (300 K) / (9 dm³)</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = 0.27 atm</p><p>P_total = P_CH4+ P_CO2= 0.55 + 0.27</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = 0.82 atm</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = 8.314 x 10⁴ Pa</p><p>Hence, the pressure exerted by a mixture is 8.314 x 10⁴ Pa</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment