8.1. Assign oxidation number to the underlined elements in each of the following species:

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Vishal Baghel | Contributor-Level 10

10 months ago

Let x be the oxidation number to the underlined elements in the given species:

(a) NaH₂PO₄

(+1) + 2 (+1) + x + 4 (-2) = 0

x + 3 – 8 = 0

x = +5

(b) NaHSO₄

(+1) + (+1) + x + 4 (-2) = 0

x – 6 = 0

x = +6

(c) H₄P₂O₇

4 (+1) + 2x + 7 (-2) = 0

2x -10 =0

x = +5

(d) K₂MnO₄

2 (+1) + x + 4 (-2) = 0

x – 6 = 0

x = +6

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