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Class 11thRedox ReactionsRedox ReactionsChemistryNcert Solutions Chemistry Class 11th

8.6. Write formulas for the following compounds:
(a) Mercury (II) chloride, (b) Nickel (II) sulphate, (c) Tin (IV) oxide, (d) Thallium
(I) sulphate, (e) Iron (III) sulphate, (f) Chromium (III) oxide.

22 Views|Posted 10 months ago
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V
10 months ago

(a) HgCl2  (b) NiSO4  (c)SnO2  (d) Tl2SO4  (e) Fe2 (S04)3  (f) Cr2O3.

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How many of these compounds will undergo disproportionation on hydrolysis? CO?, NO?, Cl?, F?, ClO?, Cl?O?, N?O?, SO?, P?O??

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Raj Pandey

2 N O 2 + 4 + H 2 O → H N O 2 + 3 + H N O + 5 3

C l 2 0 + H 2 O → H C l - 1 + H O C l

2 C l O 2 + 4 + H 2 O → H C l O 2 + 3 + H C l O 3 + 5

C l 2 + 6 O 6 + H 2 O → H C l O 3 + 5 + C l O 4 + + +

40. Best reducing agent is:
(a) He              (b) Be           (c) Li            (d) Al

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Vishal Baghel

Kindly go through the solution

(c) Li

37. Which element is considered to have oxidation number of +3 in all its compounds?

(a) Be              (b) Li             (c) Al         (d) Sc

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Vishal Baghel

Kindly go through the solution

(c) Al

36. Oxidation number ofS in S2O8-2 is

(a) -2           (b) -6           (c) +2          (d) +6

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Vishal Baghel

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(d) +6

32. Assertion: Na+ ion has an oxidation number of +1, Mg2+ ion, +2, Fe3+ ion, +3, Cl– ion, –1, O2– ion, –2; and so on.

Reason: For ions composed of only one atom, the oxidation number is equal to the charge on the ion.

VB
Vishal Baghel

Kindly go through the solution

(a)

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Chemistry Redox Reactions 2025

Chemistry Redox Reactions 2025

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