A crystal is made up of metal ions ' M₁ ' and ' M₂ ' and oxide ions. Oxide ions form a ccp lattice structure. The cation ' M₁ ' occupies 50% of octahedral voids and the cation ' M₂ ' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of ' M₁ ' and ' M₂' are respectively:
A crystal is made up of metal ions ' M₁ ' and ' M₂ ' and oxide ions. Oxide ions form a ccp lattice structure. The cation ' M₁ ' occupies 50% of octahedral voids and the cation ' M₂ ' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of ' M₁ ' and ' M₂' are respectively:
In the ccp lattice of oxide ions effective number of O? ² ions = 8 *? + 6 * ½ = 4
In the ccp lattice,
No. of octahedral voids = 4
No. of tetrahedral voids = 8
Given M? atoms occupies 50% of octahedral voids and M? atoms occupies 12.5 of tetrahedral voids
No. of M? metal atoms = 4 *? /? = 2
No. of M? meta
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Chemistry Ncert Solutions Class 12th 2023
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