A diatomic molecule X₂ has a body centered cubic (bcc). The density of the molecule is 6.17 g cm⁻³. The number of molecules present in 200 g² of X₂ is: (Avogadro constant (NA) = 6 × 10²³ mol⁻¹)
A diatomic molecule X₂ has a body centered cubic (bcc). The density of the molecule is 6.17 g cm⁻³. The number of molecules present in 200 g² of X₂ is: (Avogadro constant (NA) = 6 × 10²³ mol⁻¹)
Option 1 -
2 NA
Option 2 -
8 NA
Option 3 -
14 NA
Option 4 -
4 NA
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1 Answer
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Correct Option - 4
Detailed Solution:ρ = M/V
∴ 6.17 = (2 x MX? ) / (N? x (300 x 10? ¹? )³)
Solving MX? = 50 g
∴ No. of molecules in 200 g
= (200/50) x N? = 4 N?
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