A solution of Fe₂(SO₄)₃ is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482g of Fe. The value of x is ______. [nearest integer]

Given : 1F = 96500 C mol1

Atomic mass of Fe = 56 g mol1

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Raj Pandey | Contributor-Level 9

6 months ago

$F e^{+ 3} + 3 e^{-} \to F e$

3 Faraday is required to deposit 1 mole Fe

$? 56 g$ deposited by $3 * 96500$ C charge

$∴ 0.3482 g$ deposited by $\frac{3 * 96500}{56} * 0.3482 C = \frac{100803.9}{56} C = 1800.7 C$

$∴ Q = I t$

1800.07 = 1.5 t

$∴ t = 1200 s e c = \frac{1200}{60}$ min = 20 min

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A solution of Fe2(SO4)3 is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482g of Fe. The value of x is ______. [nearest integer] Given : 1F = 96500 C mol1 Atomic mass of Fe = 56 g mol1

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