Arrange the following carbanions in order of their decreasing stability.
(A) H3C - C ≡ C -(B) H - C ≡ C -
(C) H3C - CH2
(i) A > B > C
(ii) B > A > C
(iii) C > B > A
(iv) C > A > B
Arrange the following carbanions in order of their decreasing stability.
(A) H3C - C ≡ C -(B) H - C ≡ C - (C) H3C - CH2
(i) A > B > C
(ii) B > A > C
(iii) C > B > A
(iv) C > A > B
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(ii) The electronegativity of sp hybridization is higher than that of sp3 hybridization.
The +I effect destabilizes the carbanion.
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