Assertion: Complexes of MX6 and MX5L type (X and L are unidentate) do not show geometrical isomerism.
Reason: Geometrical isomerism is not shown by complexes of coordination number 6.
Assertion: Complexes of MX6 and MX5L type (X and L are unidentate) do not show geometrical isomerism.
Reason: Geometrical isomerism is not shown by complexes of coordination number 6.
-
1 Answer
-
This is a Assertion and Reason Type Questions as classified in NCERT Exemplar
Ans: Correct option: B
From the Cis and Trans forms, geometrical isomerism forms compounds. All of the valences in the MX6 ligand are the same, resulting in an identical molecule. L is a distinct ligand in MX5L, and it can be replaced with any other valency in the structure to create an identical molecule; the molecule does not change. Because of the presence of symmetry, which is an essential prerequisite for revealing geometrical isomerism, complexes do not show geometrical isomerism.
Similar Questions for you
CoCl3.NH3 + AgNO3
x = 5
In H2O (polar solvent) dibromophenol derivative and in CS2 (non-polar solvent moneobromo phenol derivate is obtained.
3d => 4d => 5d CFSE increases for the same ligands.
Factual
⇒ leaching methods is used for those metal in which metal is more soluble than impurities and these are Al, Au, Ag, low grade Cu
σ bonded organometallic compound ⇒ M – C
σ-bond
and in π – bonded organo metallic compound
M – C
π bond
In ferrocene, there is π-bond
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers